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Unit 5 Key Questions Chemistry Lesson 17: 61A. B. C. 62A. 5.6 X 10-12= ( x)2 ( 0.050 groyne/L) sq. germ (1.12X10-10) =x B. Ksp for PbCl2 = 1.6 x 10^-5 moles Pb2+ = 0.0200 L x 2.50 x 10^-4 = 5.00 x 10^-6 moles CaCl2 = 0.0450 L x 1.25 x 10^-3 = 5.63 x 10^-5 moles Cl- = 2 x 5.63 x 10^-5 =1.13 x 10^-4 integral majority = 20.0 + 45.0 = 65.0 mL = 0.0650 L [Pb2+] = 5.00 x 10^-6 mol/ 0.0650 L=7.69 x 10^-5 M [Cl-]= 1.13 x 10^-4 / 0.0650 = 0.00174 Qsp = [Pb2+][Cl-]^2 = 7.69 x 10^-5 ( 0.00174)^2 = 2.32 x 10^-10 <<< Ksp venturesomeness should NOT occur Lesson 18: 63A. Beca use of goods and services hop up is something the chemical chemical reaction arises, it is exothermic (meaning heat is released as a product). BI. Amphoteric intend that the substance can serve as either a base or an pane. In this case, H2PO4- is phosphoric acid that has woolly-headed one of its reactive hydronium ions (H+ or, technically, H3O+) II. H2PO4- + HS- = H3PO4 + S2- 64A . Kb = [6.31*10^-5]²/0.32 Kb = 3.98*10^-9/0.32 Kb = 1.24*10^-8 B. H+] = 10^-pH [H+] = 10^-2.96 [H+] = 1.10*10^-3 Ka = [1.1*10^-3]² / 0.10 Ka = 1.20*10^-6/0.10 Ka = 1.20*10^-5 C. D. Lesson 19: 65. moles HF = 0.0100 L x 0.250 mol/L = 0.00250 moles NaOH postulate to reach the comparability point = 0.00250 volume NaOH = 0.00250 mol/ 0.100 mol/L = 0.0250 L total volume = 0.0250 + 0.

0100 = 0.0350 L the reaction of neutralization is HF + NaOH = NaF + H2O moles NaF formed = 0.00250 NaF is a warm salt : NaF = Na+ + F- [F-]= 0.00250 mol / 0.0350 L=0.0714 M the correspondence is F- + H2O <=> HF + OH- Kb = Kw/ Ka = 1.0 x 10^-14 / 6.8 x 10^-4 = 1.5 x 10^-11 =! x^2 / 0.0714-x x = [OH-]= 1.03 x 10^-6 M pOH = 5.99 pH = 14 - 5.99= 8.01 66A. HC9H7O4(aq) + NaOH(aq) = NaC9H7O4(aq) + H2O(l) B. you atomic number 18 reacting a weak acid with strong base - use phenolphthalein indicator C. D. E. Damaged and pain-causing cells produce large quantities of an enzyme called cylooxygenase-2. This enzyme in turn produces a chemical called prostaglandin, which sends...If you penury to get a full essay, consecrate it on our website: BestEssayCheap.com

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